## 2020N0229

### MathJaxŕꕪq̍قȂ镪͂ފʂ̍𒲐Ƃ

NbN11X肢܂B

ʂ\left\rightɂ鍂̎sOłB
$\frac{a^n}{n^k}=\left[\frac{\left(a^{\scriptsize\dfrac{1}{k}}\right)^n}{n}\right]^k\gt M^k\gt M$
\lower{1.8ex}ŁAʓ̕܂B
$\dfrac{a^n}{n^k}=\left[\lower{1.8ex}\dfrac{\left(a^{\scriptsize\dfrac{1}{k}}\right)^n}{n}\right]^k\gt M^k\gt M$

posted by Line Segment at 18:00 | Comment(0) | L | |